document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=846852>Question 846852</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What's the steps to solving v+(1/8)=(3/4) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #509949 by </B><A HREF=/tutors/aboutme.mpl?userid=pmesler><B>pmesler(52)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=pmesler><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=pmesler><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=509949\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Simply subtract each side by 1/8.\r<BR>\n" );
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document.write( "v = 3/4 - 1/8 \r<BR>\n" );
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document.write( "Because the denominators are different, you need to multiply 3/4 by 2/2. That will make the denominator change to 8. \r<BR>\n" );
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document.write( "v = 3/4(2/2) - 1/8\r<BR>\n" );
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document.write( "v = 6/8 - 1/8 \r<BR>\n" );
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document.write( "v = 5/8. \r<BR>\n" );
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document.write( "Let's plug in v's value in the original equation\r<BR>\n" );
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document.write( "5/8+1/8 = 3/4 \r<BR>\n" );
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document.write( "6/8 = 3/4 \r<BR>\n" );
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document.write( "Reduce the left side by dividing the numerator and denominator by 2/2\r<BR>\n" );
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document.write( "6/8 div (2/2) = 3/4\r<BR>\n" );
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document.write( "3/4 = 3/4. It checks out. So v = 5/8 is the correct answer.  </SPAN>\n" );
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