document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=846857>Question 846857</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi there, I have a quiz tommorow on Substitution and Elimination. I know how to do both, but sadly I am not the sharpest when it comes to word problems. I am stuck with this one. \r<BR>\n" );
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document.write( "Mrs. Lincoln mixes two brands of coffee to make 15 pounds of a mixture selling for $4.78 per pound. She mixes monson coffee selling at 3.90 per pound, with Valley Brothers coffee selling at $5.75 per pound. How many pounds of each coffee should she use in the mixture. \r<BR>\n" );
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document.write( "The part I get confused at is how you can mix the two but get something worth less. It would be ideal to get this as soon as possible if not that is ok, I respect your time and do not wish to waste it. Thanks in advance </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #509948 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=509948\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Mrs. Lincoln mixes two brands of coffee to make 15 pounds of a mixture selling for $4.78 per pound. She mixes monson coffee selling at 3.90 per pound, with Valley Brothers coffee selling at $5.75 per pound. How many pounds of each coffee should she use in the mixture. <BR>\n" );
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document.write( "t = amount of $3.90<BR>\n" );
document.write( "f = amount of $5.75<BR>\n" );
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document.write( "t + f = 15 (total coffee)<BR>\n" );
document.write( "t*390 + f*575 = 15*478 (total price)<BR>\n" );
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document.write( "f = 15 - t<BR>\n" );
document.write( "390t + 575f = 7170<BR>\n" );
document.write( "78t + 115f = 1434<BR>\n" );
document.write( "78t + 115*(15-t) = 1434<BR>\n" );
document.write( "etc\r<BR>\n" );
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