document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=846860>Question 846860</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Evaluate 2log_6(6x)-log_6(x)^2<BR>\n" );
document.write( "For whatvalues of x is the value of this expression valid? Explain.<BR>\n" );
document.write( "Thank you.xx </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #509945 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=509945\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The arguments (basically the terms in the logs) must be positive. You cannot take the log of 0 or a negative number.\r<BR>\n" );
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document.write( "So both 6x and x must be greater than 0. \r<BR>\n" );
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document.write( "So...\r<BR>\n" );
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document.write( "6x > 0\r<BR>\n" );
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document.write( "x > 0/6\r<BR>\n" );
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document.write( "x > 0\r<BR>\n" );
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document.write( "Which means that <font color=\"red\">x > 0</font> in order for the expression to be valid. </SPAN>\n" );
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