document.write( "Question 846843: Trying to understand how
\n" ); document.write( " n^2+5n+100-[(n-1)^2+5(n-1)+100]= 2n+4
\n" ); document.write( "Need to see steps to understand please
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Algebra.Com's Answer #509938 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
What can you do inside parentheses (or other groupings) first?\r
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\n" ); document.write( "\n" ); document.write( "n^2+5n+100-[(n-1)^2+5(n-1)+100] ----------- See distributive property possible?
\n" ); document.write( "n^2+5n+100-((n-1)^2+5n-5+100)
\n" ); document.write( "n^2+5n+100-((n-1)^2+5n+95)\r
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\n" ); document.write( "\n" ); document.write( "Anything more inside parentheses?\r
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\n" ); document.write( "\n" ); document.write( "n^2+5n+100-(n^2-2n+1+5n+95)
\n" ); document.write( "and still working inside parentheses,
\n" ); document.write( "n^2+5n+100-(n^2+3n+96)\r
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\n" ); document.write( "\n" ); document.write( "Next, understand you are subtracting EVERYTHING inside the parenthesized expression:
\n" ); document.write( "n^2+5n+100-n^2-3n-96
\n" ); document.write( "Obviously, combine like-terms:
\n" ); document.write( "n^2-n^2+5n-3n+100-96
\n" ); document.write( "2n+4 \n" ); document.write( "
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