document.write( "Question 846790: In 3 years, Jeff will be twice as old as he was 4 years ago. How old is Jeff now? \n" ); document.write( "
Algebra.Com's Answer #509935 by josh_jordan(263)\"\" \"About 
You can put this solution on YOUR website!
To solve, we need to set this word problem up as an equation. Let's break down each word (series of words):\r
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\n" ); document.write( "\n" ); document.write( "In 3 years: + 3\r
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\n" ); document.write( "\n" ); document.write( "Jeff: J\r
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\n" ); document.write( "\n" ); document.write( "will be: =\r
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\n" ); document.write( "\n" ); document.write( "twice as old as he was 4 years ago = 2(J - 4)\r
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\n" ); document.write( "\n" ); document.write( "Now let's put all of this together:\r
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\n" ); document.write( "\n" ); document.write( "J + 3 = 2(J - 4)\r
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\n" ); document.write( "\n" ); document.write( "Now we have an equation we can solve. First, distribute the 2 to (J - 4):\r
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\n" ); document.write( "\n" ); document.write( "J + 3 = 2J - 8\r
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\n" ); document.write( "\n" ); document.write( "Subtract J from both sides of the equal sign:\r
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\n" ); document.write( "\n" ); document.write( "J - J + 3 = 2J - J - 8 ----->\r
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\n" ); document.write( "\n" ); document.write( "3 = J - 8\r
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\n" ); document.write( "\n" ); document.write( "Finally, add 8 to both sides of the equal sign:\r
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\n" ); document.write( "\n" ); document.write( "3 + 8 = J - 8 + 8 ----->\r
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\n" ); document.write( "\n" ); document.write( "11 = J\r
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\n" ); document.write( "\n" ); document.write( "Therefore, Jeff is 11 years old.\r
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