document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=846766>Question 846766</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A father's age is three times the sum of the ages of his two children. In four years, he will be twice as old as the sum of their ages. How old is the father? Only an algebraic solution will be accepted.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #509933 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=509933\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let f = father's present age<BR>\n" );
document.write( "let s = sum of the children's ages now<BR>\n" );
document.write( ":<BR>\n" );
document.write( "A father's age is three times the sum of the ages of his two children.<BR>\n" );
document.write( "f = 3s <BR>\n" );
document.write( "In four years, he will be twice as old as the sum of their ages.<BR>\n" );
document.write( "f + 4 = 2(s+8); both children will age 4 yrs<BR>\n" );
document.write( "f = 4 = 2s + 16<BR>\n" );
document.write( "f = 2s + 16 - 4<BR>\n" );
document.write( "f = 2s + 12<BR>\n" );
document.write( "Replace f with 3s from the 1st equation<BR>\n" );
document.write( "3s = 2s + 12<BR>\n" );
document.write( "3s - 2s = 12<BR>\n" );
document.write( "s = 12 is the sum of his childen<BR>\n" );
document.write( "then<BR>\n" );
document.write( "f = 3(12)<BR>\n" );
document.write( "f = 36 yrs is the father's present age\r<BR>\n" );
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document.write( " </SPAN>\n" );
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