document.write( "Question 71283This question is from textbook Algebra
\n" ); document.write( ": b/b-1 + 2b/b^2-1 simplify \n" ); document.write( "
Algebra.Com's Answer #50991 by sudhir(14)\"\" \"About 
You can put this solution on YOUR website!
You wrote \" b/b-1 + 2b/b^2-1 simplify\" but sorry to say this is a lousy way to write an expression as it has changed the meaning . Instead should have been
\n" ); document.write( "written as :- \" b/(b-1) + 2b/(b^2-1) simplify\".\r
\n" ); document.write( "\n" ); document.write( "Now,
\n" ); document.write( " b/(b-1) + 2b/(b^2-1)
\n" ); document.write( "= b(b+1)/((b-1)(b+1)) + 2b/(b^2-1) as (b-1)(b+1)=b^2-1 so you can say that i have made the denominators of the two terms equal.\r
\n" ); document.write( "\n" ); document.write( "= b(b+1)/((b-1)(b+1)) + 2b/((b-1)(b+1))
\n" ); document.write( "= (b^2 + b + 2b)/((b-1)(b+1))
\n" ); document.write( "= (b^2 + 3b)/((b-1)(b+1))
\n" ); document.write( "= b(b+3)/((b-1)(b+1)) Answer.
\n" ); document.write( "cheers!
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