document.write( "Question 71286: This is a digit problem. I apologize if I am in the wrong area. The question is;\r
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document.write( "The sum of the digits of the two-digit numeral is 8. The number with the digits interchanged is 7 times the tens digit of the original number. Find the original number\r
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document.write( "Thanks for your help!\r
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document.write( "C. Johnson \n" );
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Algebra.Com's Answer #50990 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The sum of the digits of the two-digit numeral is 8. The number with the digits interchanged is 7 times the tens digit of the original number. Find the original number \n" ); document.write( "------------- \n" ); document.write( "Let the two digit number be tu where t is the \"ten's\" digit and u and the \"unit's digit. Also keep in mind that tu =10t+u just like 23 = 10*2+3. \n" ); document.write( "--------- \n" ); document.write( "EQUATIONS: \n" ); document.write( "t+u=8 \n" ); document.write( "10u+t = 7t \n" ); document.write( "------- \n" ); document.write( "Solve the 1st for t: t=8-u \n" ); document.write( "Siplify the 2nd then, \n" ); document.write( "Substitute t=8-u into the 2nd: \n" ); document.write( "10u=6t \n" ); document.write( "10u=6(8-u) \n" ); document.write( "10u = 48-6u\r \n" ); document.write( "\n" ); document.write( "16u=48 \n" ); document.write( "u=3 \n" ); document.write( "The t=8-u=8-3=5 \n" ); document.write( "----------------- \n" ); document.write( "The original number is 53 \n" ); document.write( "----------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |