document.write( "Question 846746: Frank makes and sells small picture frames. His revenue from sales can be represented as R=$13.60x for x frames sold. The cost of making the frames can be represented as C=$5.80x +$120 for x frames made. What is the minimum number of frames Frank must sell in order for his revenue to be greater than his costs.
\n" ); document.write( "Please help, I can't wrap my head around this one. Thanks, Karl\r
\n" ); document.write( "\n" ); document.write( "pistolpest2000@yahoo.com \n" ); document.write( "

Algebra.Com's Answer #509896 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
If profit = $\"+P+\"$ , then $\"+P+=+R+-+C+\"$
\n" ); document.write( " $\"+P+=+13.6x+-+%28+5.8x+%2B+120+%29+\"$
\n" ); document.write( " $\"+P+=+13.6x+-+5.8x+-+120+\"$
\n" ); document.write( " $\"+P+=+7.8x+-+120+\"$
\n" ); document.write( "Make the profit zero, which means $\"+R+=+C+\"$
\n" ); document.write( " $\"+7.8x+-+120+=+0+\"$
\n" ); document.write( " $\"+7.8x+=+120+\"$
\n" ); document.write( " $\"+x+=+15.385+\"$
\n" ); document.write( "You can't have a fraction of a frame,
\n" ); document.write( "so the profit is zero when Frank sells
\n" ); document.write( "15 frames, and he begins to make a
\n" ); document.write( "profit when he sells 16 frames
\n" ); document.write( "---------------
\n" ); document.write( "check:
\n" ); document.write( " $\"+P+=+7.8x+-+120+\"$
\n" ); document.write( " $\"+0+=+7.8%2A15.385+-+120+\"$
\n" ); document.write( " $\"+0+=+120.003+-+120+\"$
\n" ); document.write( " $\"+0+=+.003+\"$
\n" ); document.write( "close enough\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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