document.write( "Question 846615: A train leaves a station at noon traveling north at an average speed of 30 mph.
\n" ); document.write( "A second train leaves the same station at 3:00 P.M. and travels south at 45 mph. \r
\n" ); document.write( "\n" ); document.write( "At what time will the trains be 500 miles apart?
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Algebra.Com's Answer #509844 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
\"D1=30%2A%28T%2B3%29\"
\n" ); document.write( "\"D2=45%2AT\"
\n" ); document.write( "where T is zero at 3:00.
\n" ); document.write( "Find T when D=500.
\n" ); document.write( "\"D=D1%2BD2\"
\n" ); document.write( "\"30%2A%28T%2B3%29%2B45%2AT=500\"
\n" ); document.write( "\"30T%2B90%2B45=500\"
\n" ); document.write( "\"30T=365\"
\n" ); document.write( "\"T=365%2F30=73%2F6=12%2B1%2F6\"hours
\n" ); document.write( "1/6 hour = 10 minutes.
\n" ); document.write( "SInce time was zero at 3:00 PM, the trains will be 500 miles apart at 3:10AM.
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