document.write( "Question 846547: I AM STUCK WITH THIS ONE AND IT IS MOST OFTEN ASKED SO PLEASE HELP ME !! 2 ( x-1 / x+3 ) -7 ( x+3 / x-1 ) = 5 \n" ); document.write( "
Algebra.Com's Answer #509825 by josh_jordan(263)\"\" \"About 
You can put this solution on YOUR website!
\"2%28%28x-1%29%2F%28x%2B3%29%29-7%28%28x%2B3%29%2F%28x-1%29%29=5\"\r
\n" ); document.write( "\n" ); document.write( "The first thing we need to do is multiply 2 by (x - 1) and multiply 7 by (x + 3):\r
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\n" ); document.write( "\n" ); document.write( "\"%28%282x-2%29%2F%28x%2B3%29%29-%28%287x%2B21%29%2F%28x-1%29%29=5\"\r
\n" ); document.write( "\n" ); document.write( "Next, we need to subtract the remaining fractions on the left side of the equation. We do this by multiplying (2x - 2) by (x - 1) and multiplying (7x + 21) by (x + 3) and setting this result in the numerator and setting (x + 3)(x - 1) in the denominator:\r
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\n" ); document.write( "\n" ); document.write( " ----->\r
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\n" ); document.write( "\n" ); document.write( "Next, after distributing the minus sign to (7x^2 + 42x + 63), combine all of the terms in the numerator and set that above the denominator:\r
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\n" ); document.write( "\n" ); document.write( "\"%282x%5E2-4x%2B2-7x%5E2-42x-63%29%2F%28%28x%2B3%29%28x-1%29%29=5\" ----->\r
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\n" ); document.write( "\n" ); document.write( "\"%28-5x%5E2-46x-61%29%2F%28%28x%2B3%29%28x-1%29%29=5\"\r
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\n" ); document.write( "\n" ); document.write( "Next, since this single fraction is set equal to a number, we will cross-multiply the numerator in the fraction, by 1, since 5 = 5/1, and multiply the denominator in the fraction by 5:\r
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\n" ); document.write( "\n" ); document.write( "\"-5x%5E2-46x-61=5%28x%2B3%29%28x-1%29\" ----->\r
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\n" ); document.write( "\n" ); document.write( "\"-5x%5E2-46x-61=5%28x%5E2%2B2x-3%29\" ----->\r
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\n" ); document.write( "\n" ); document.write( "\"-5x%5E2-46x-61=5x%5E2%2B10x-15\"\r
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\n" ); document.write( "\n" ); document.write( "Now, since this is a quadratic equation, we need to move all of the terms to one side of the equation and set the other side of the equation equal to 0:\r
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\n" ); document.write( "\n" ); document.write( "\"0=5x%5E2%2B5x%5E2%2B10x%2B46x-15%2B61\"\r
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\n" ); document.write( "\n" ); document.write( "Combining like terms gives us:\r
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\n" ); document.write( "\n" ); document.write( "\"0=10x%5E2%2B56x%2B46\"\r
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\n" ); document.write( "\n" ); document.write( "Now we have this in quadratic form. Let's make this equation easier to factor by factoring out 2, giving us:\r
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\n" ); document.write( "\n" ); document.write( "\"0=2%285x%5E2%2B28x%2B23%29\"\r
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\n" ); document.write( "\n" ); document.write( "Now, this is easily factorable:\r
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\n" ); document.write( "\n" ); document.write( "\"0=2%285x%2B23%29%28x%2B1%29\"\r
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\n" ); document.write( "\n" ); document.write( "We can discard the 2 we factored out, and set each of our factors equal to zero to find our x's:\r
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\n" ); document.write( "\n" ); document.write( "\"5x%2B23=0\" ----->\r
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\n" ); document.write( "\n" ); document.write( "\"5x=-23\" ----->\r
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\n" ); document.write( "\n" ); document.write( "\"x=-23%2F5\"\r
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\n" ); document.write( "\n" ); document.write( "AND\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B1=0\" ----->\r
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\n" ); document.write( "\n" ); document.write( "\"x=-1\"\r
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\n" ); document.write( "\n" ); document.write( "We now have solved for x.\r
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\n" ); document.write( "\n" ); document.write( "x = -1 and -23/5\r
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\n" ); document.write( "\n" ); document.write( "You need to verify both of these values of x work by plugging each value of x into the original equation. Both, in fact, do work, so\r
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\n" ); document.write( "\n" ); document.write( "x = -1 and -23/5\r
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