document.write( "Question 71260: Can someone show me the answer to this question from a previous exam i have recently take please. thankyou.\r
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document.write( "Emperical Rule\r
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document.write( "Approximately what percentage of people have temperatures between 96.34 and 98.2 degrees? \n" );
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Algebra.Com's Answer #50980 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Question 1: Emperical Rule \n" ); document.write( "Human body temperature have a mean of 98.20 degrees a standard deviation of 0.62 degrees. \n" ); document.write( "a. Approximately what percentage of people have temperatures between 97.58 and 98.82 degrees? (Hint: Use a number line and the Emperical Rule.) \n" ); document.write( "Find the z-value of each temperature value: \n" ); document.write( "(97.58-98.2)/0.62 = -1 \n" ); document.write( "(98.82-98.2)/0.62 = +1 \n" ); document.write( "According to Emperical Rule 68% of the people have temperatures in that range. \n" ); document.write( "------------------------- \n" ); document.write( "b. Approximately what percentage of people have temperatures between 96.34 and 98.2 degrees? \n" ); document.write( "same procedure: find the z-values of the given termperatures; \n" ); document.write( "z(96.34) = (96.34-98.2)/0.62 = -3 \n" ); document.write( "z(98.2)= (98.2-98.2)/0.62 =0 \n" ); document.write( "-------- \n" ); document.write( "According to the Empirical rul 99% of the population is within 3 standard \n" ); document.write( "deviations. You have only the left half of that distribution. You answer \n" ); document.write( "is 99/2 = 49.5% \n" ); document.write( "------------------ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "--------------- \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |