document.write( "Question 71260: Can someone show me the answer to this question from a previous exam i have recently take please. thankyou.\r
\n" ); document.write( "\n" ); document.write( "Emperical Rule\r
\n" ); document.write( "\n" ); document.write( "Approximately what percentage of people have temperatures between 96.34 and 98.2 degrees?
\n" ); document.write( "

Algebra.Com's Answer #50980 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Question 1: Emperical Rule
\n" ); document.write( "Human body temperature have a mean of 98.20 degrees a standard deviation of 0.62 degrees.
\n" ); document.write( "a. Approximately what percentage of people have temperatures between 97.58 and 98.82 degrees? (Hint: Use a number line and the Emperical Rule.)
\n" ); document.write( "Find the z-value of each temperature value:
\n" ); document.write( "(97.58-98.2)/0.62 = -1
\n" ); document.write( "(98.82-98.2)/0.62 = +1
\n" ); document.write( "According to Emperical Rule 68% of the people have temperatures in that range.
\n" ); document.write( "-------------------------
\n" ); document.write( "b. Approximately what percentage of people have temperatures between 96.34 and 98.2 degrees?
\n" ); document.write( "same procedure: find the z-values of the given termperatures;
\n" ); document.write( "z(96.34) = (96.34-98.2)/0.62 = -3
\n" ); document.write( "z(98.2)= (98.2-98.2)/0.62 =0
\n" ); document.write( "--------
\n" ); document.write( "According to the Empirical rul 99% of the population is within 3 standard
\n" ); document.write( "deviations. You have only the left half of that distribution. You answer
\n" ); document.write( "is 99/2 = 49.5%
\n" ); document.write( "------------------
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "--------------- \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );