document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=846542>Question 846542</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1)A particle moves along the top of the parabola y^2=2x from left to right at a constant speed of 5 units per second. Find the velocity of the particle as it moves through the point (2,2).\r<BR>\n" );
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document.write( "2)The quarterback of a football team releases a pass at a height of 7 feet above the playing field, and the football is caught by a receiver 30 yards directly downfield at a height of 4 feet. The pass is released at an angle of 350 with the horizontal.\r<BR>\n" );
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document.write( "	Find the speed of the football when it is released.<BR>\n" );
document.write( "	Find the maximum height of the football.<BR>\n" );
document.write( "	Find the time the receiver has to reach the proper position after the quarterback releases the football.\r<BR>\n" );
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document.write( "Question 3\r<BR>\n" );
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document.write( "	Evaluate the double integral over the given region R:\r<BR>\n" );
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document.write( "	&#8748;&#9618;( xy^3)/(x^(2 )+ 1) dA,R:0&#8804;x&#8804;1,0&#8804;y&#8804;2\r<BR>\n" );
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document.write( "	&#8748;&#9618;&#12310;xye^(&#12310;xy&#12311;^2 ) &#12311;  dA,R:0&#8804;x&#8804;2,0&#8804;y&#8804;1\r<BR>\n" );
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document.write( "	&#8748;&#9618;&#12310;y sin&#8289;&#12310;(x+y)&#12311;  &#12311;  dA,R: -&#960;&#8804;x&#8804;0,0&#8804;y&#8804;&#960;\r<BR>\n" );
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document.write( "5)Find the volume of the region bounded above the paraboloid z= x^2+ y^2 and below by the triangle enclosed by the lines y=x,x=0 and x+y=2 in the xy plane.\r<BR>\n" );
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document.write( "6)Find the area of the region that lies inside the cardioid  r=1+cos&#8289;&#952; and outside the circle r=1.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #509796 by </B><A HREF=/tutors/aboutme.mpl?userid=psbhowmick><B>psbhowmick(878)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=psbhowmick><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=psbhowmick><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=509796\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1) Velocity of the particle along parabola is in the direction of its tangent.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=dy%2Fdx+=+1%2Fy+=+1%2Fsqrt%282x%29 ALIGN=MIDDLE  ALT=\"dy%2Fdx+=+1%2Fy+=+1%2Fsqrt%282x%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "At (2,2), <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=dy%2Fdx+=+1%2Fsqrt%282%2A2%29=1%2F2 ALIGN=MIDDLE  ALT=\"dy%2Fdx+=+1%2Fsqrt%282%2A2%29=1%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "Let the velocity be represented by: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=V+=+5cos%28theta%29i+%2B+5sin%28theta%29j ALIGN=MIDDLE  ALT=\"V+=+5cos%28theta%29i+%2B+5sin%28theta%29j\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=tan%28theta%29=dy%2Fdx+=+1%2F2 ALIGN=MIDDLE  ALT=\"tan%28theta%29=dy%2Fdx+=+1%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sec%28theta%29+=+sqrt%281+%2B+tan%5E2%28theta%29%29+=+sqrt%281+%2B+1%2F4%29+=+sqrt%285%29%2F2 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=cos%28theta%29=2%2Fsqrt%285%29 ALIGN=MIDDLE  ALT=\"cos%28theta%29=2%2Fsqrt%285%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sin%28theta%29+=+sqrt%281+-+cos%5E2%28theta%29%29+=+sqrt%281+-+4%2F5%29+=+1%2Fsqrt%285%29 ALIGN=MIDDLE  ALT=\"sin%28theta%29+=+sqrt%281+-+cos%5E2%28theta%29%29+=+sqrt%281+-+4%2F5%29+=+1%2Fsqrt%285%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Thus, the velocity vector is:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=V+=+5%28%282%2Fsqrt%285%29%29i+%2B+%281%2Fsqrt%285%29%29j%29 ALIGN=MIDDLE  ALT=\"V+=+5%28%282%2Fsqrt%285%29%29i+%2B+%281%2Fsqrt%285%29%29j%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=V+=+2%2Asqrt%285%29i+%2B+sqrt%285%29j%29 ALIGN=MIDDLE  ALT=\"V+=+2%2Asqrt%285%29i+%2B+sqrt%285%29j%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "If you want help with the remaining questions then send me an email. I can solve them on paper, scan and send you. Cheers!!! </SPAN>\n" );
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