document.write( "Question 71246: Please help me solve this problem\r
\n" ); document.write( "\n" ); document.write( "An object is projected upward from the top of the tower. it's distance in feet above the ground after t seconds is given by s(f)=-16t^2 +64t +80. How many seconds will it take to reach ground level?\r
\n" ); document.write( "\n" ); document.write( "I would really like to know how to figure this out.
\n" ); document.write( "Thanks to anyone who is willing to help me
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Algebra.Com's Answer #50978 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
After t seconds, the height of an object with an initial upward velocity of \"v%5Bo%5D\" feet per second and an initial height of \"h%5Bo%5D\" feet is given by the function: \"s%28t%29+=+-16t%5E2%2Bv%5Bo%5Dt%2Bh%5Bo%5D\"
\n" ); document.write( "In your problem, \"v%5Bo%5D+=+64\"ft/sec and \"h%5Bo%5D+=+80\"ft, so you have:
\n" ); document.write( "\"s%28t%29+=+-16t%5E2%2B64t%2B80\"
\n" ); document.write( "You want to know at what time, t, will the height, h, be 0, so set the function s(t) = 0 and solve for t.
\n" ); document.write( "\"-16t%5E2%2B64t%2B80+=+0\" You can simplify this a bit by factoring out -16.
\n" ); document.write( "\"-16%28t%5E2-4t-5%29+=+0\" so:
\n" ); document.write( "\"t%5E2-4t-5+=+0\" You can factor this quadratic equation.
\n" ); document.write( "\"%28t%2B1%29%28t-5%29+=+0\" Apply the zero product principle.
\n" ); document.write( "\"t%2B1+=+0\" and/or \"t-5+=+0\"
\n" ); document.write( "If \"t%2B1+=+0\" then \"t+=+-1\" Discard this solution as the time must be a positive value.
\n" ); document.write( "If \"t-5+=+0\" then \"t+=+5\"
\n" ); document.write( "So the object will reach ground-level (h=0) in 5 seconds.
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