document.write( "Question 846511: One question with 3 answers: dont need to show work. Thank you!\r
\n" ); document.write( "\n" ); document.write( "Twenty percent of American households own three or more cars. A random sample of 100 American households is selected. Let X be the number of households selected that own three or more cars. \r
\n" ); document.write( "\n" ); document.write( "The standard deviation of X is ______\r
\n" ); document.write( "\n" ); document.write( "The mean of X is ____\r
\n" ); document.write( "\n" ); document.write( "The probability that at least 28 of the households selected own at least three or more cars is _______\r
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Algebra.Com's Answer #509767 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

 
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document.write( "Hi,
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document.write( "p = .20,  n = 100
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document.write( "mean = 
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document.write( "variance =s 
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document.write( "SD =  = 4
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document.write( "P(x ≥ 28) = 1 - binomcdf(n, p, largest x-value) = 1 - binomcdf(100, .20,)= 1 -  .9658 = .0342  0r 3.42 %
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