document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=846488>Question 846488</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help me solve this. <BR>\n" );
document.write( "1.) One number is thrice another number. If their difference is 14, what are the numbers.<BR>\n" );
document.write( "2.) andy is seven years older than Mel.ten years ago, he was twice as old as Mel. Find their present ages.\r<BR>\n" );
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document.write( "thanks so much! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #509766 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=509766\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1) let x be one number and 3x the other, then<BR>\n" );
document.write( "3x - x = 14<BR>\n" );
document.write( "2x = 14<BR>\n" );
document.write( "x = 7<BR>\n" );
document.write( "the numbers are 7 and 21<BR>\n" );
document.write( "2) Andy = Mel + 7<BR>\n" );
document.write( "Andy - 10 = 2*(Mel - 10)<BR>\n" );
document.write( "substitute for Andy in second equation<BR>\n" );
document.write( "Mel + 7 - 10 = 2 * (Mel - 10)<BR>\n" );
document.write( "Mel -3 = 2Mel -20<BR>\n" );
document.write( "Mel = 17 years old<BR>\n" );
document.write( "Andy = 24 years old\r<BR>\n" );
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