document.write( "Question 846485: The probability that an American household has a gun is 0.34 . Five American households are selected at random. (Report answers rounded to four decimal places.
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\n" ); document.write( "(a) What is the probability that exactly two of the five households have a gun?
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\n" ); document.write( "\n" ); document.write( "(b) What is the probability that none of the five households has a gun?
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\n" ); document.write( "\n" ); document.write( "(c) What is the probability that all five of the households have a gun?
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\n" ); document.write( "\n" ); document.write( "(d) What is the probability that at least one of the five households has a gun?
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Algebra.Com's Answer #509758 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
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\n" ); document.write( "Note: The probability of x successes in n trials is:
\n" ); document.write( "P = nCx* \"p%5Ex%2Aq%5E%28n-x%29\" where p and q are the probabilities of success and failure
\n" ); document.write( "p = .34, n = 5
\n" ); document.write( "TI or long hand
\n" ); document.write( "P(x=2) = binompdf(n, p, x-value)= binompdf(5, .34, 2) Or 5C2 \"%28.34%29%5E2%2A%28.66%29%5E3\" = 10\"%28.34%29%5E2%2A%28.66%29%5E3\"
\n" ); document.write( "P(x =0)= binompdf(n, p, x-value)= binompdf(5, .34, 0) 0r \"%28.34%29%5E0%2A%28.66%29%5E5\"
\n" ); document.write( "P(x =5)= binompdf(n, p, x-value)= binompdf(5, .34, 5) 0r \"%28.34%29%5E5%2A%28.66%29%5E0\"
\n" ); document.write( "P(x ≥ 1) = 1 -binomcdf(n, p, largest x-value) = 1 -binomcdf(5 .34. 0) \n" ); document.write( "
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