document.write( "Question 846462: I need to calculate a mixture of 2 products:
\n" ); document.write( "Mixture A = 58% of B + 42% of C
\n" ); document.write( "A B C are all volumes in liters
\n" ); document.write( "B is a known value.
\n" ); document.write( "How do I calculate C\r
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Algebra.Com's Answer #509726 by KMST(5328)\"\" \"About 
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\"A\"= volume of mixture A
\n" ); document.write( "\"B\"= volume of product B in mixture A
\n" ); document.write( "\"C\"= volume of product C in mixture A
\n" ); document.write( "Mixture A is made of 58% of product B and 42% of product C.
\n" ); document.write( "We assume that volumes are additive (or very nearly so),
\n" ); document.write( "meaning that \"A=B%2BC\" .
\n" ); document.write( "B is 58% of A, so \"B=%2858%2F100%29%2AA\" or \"B=0.58A\"
\n" ); document.write( "C is 42% of A, so \"C=%2842%2F100%29%2AA\" or \"C=0.42A\"
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\n" ); document.write( "With \"B=0.58A\" and \"C=0.42A\" ,
\n" ); document.write( "given any one of the volumes, you can calculate the other two volumes.
\n" ); document.write( "If you know \"B\" ,
\n" ); document.write( "\"B=0.58A\" --> \"B%2F0.58=A\" --> \"highlight%28A=B%2F0.58%29\" .
\n" ); document.write( "Then,
\n" ); document.write( "\"system%28C=0.42A%2CA=B%2F0.58%29\" --> \"C=0.42%28B%2F0.58%29\" --> \"highlight%28C=0.42%2AB%2F0.58%29\" or \"highlight%28C=%2842%2F58%29%2AB%29\"
\n" ); document.write( "That can be calculated as approximately \"C=0.724%2AB%29\" .
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