document.write( "Question 846234: Jim can run 5 miles per hour on level ground on a still day. One windy day he runs 15 miles with the wind and in the same amount of time runs 4 miles against the wind. What is the rate of the wind? \n" ); document.write( "
Algebra.Com's Answer #509663 by josmiceli(19441)\"\" \"About 
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Let \"+t+\" = his time for running both
\n" ); document.write( "with the wind and against the wind
\n" ); document.write( "Let \"+w+\" = the speed of the wind
\n" ); document.write( "--------------------------------
\n" ); document.write( "With the wind:
\n" ); document.write( "(1) \"+15+=+%28+5+%2B+w+%29%2At+\"
\n" ); document.write( "Against the wind:
\n" ); document.write( "(2) \"+4+=+%28+5+-+w+%29%2At+\"
\n" ); document.write( "---------------------
\n" ); document.write( "(1) \"+15+=+5t+%2B+w%2At+\"
\n" ); document.write( "and
\n" ); document.write( "(2) \"+4+=+5t+-+w%2At+\"
\n" ); document.write( "---------------------
\n" ); document.write( "Add the equations:
\n" ); document.write( "(1) \"+15+=+5t+%2B+w%2At+\"
\n" ); document.write( "(2) \"+4+=+5t+-+w%2At+\"
\n" ); document.write( "\"+19+=+10t+\"
\n" ); document.write( "\"+t+=+1.9+\"
\n" ); document.write( "and
\n" ); document.write( "(2) \"+4+=+%28+5+-+w+%29%2A1.9+\"
\n" ); document.write( "(2) \"+4+=+9.5+-+1.9w+\"
\n" ); document.write( "(2) \"+1.9w+=+5.5+\"
\n" ); document.write( "(2) \"+w+=+2.895+\"
\n" ); document.write( "check:
\n" ); document.write( "(1) \"+15+=+%28+5+%2B+w+%29%2At+\"
\n" ); document.write( "(1) \"+15+=+%28+5+%2B+2.895+%29%2A1.9+\"
\n" ); document.write( "(1) \"+15+=+7.895%2A1.9+\"
\n" ); document.write( "(1) \"+15+=+15.0005+\"
\n" ); document.write( "and
\n" ); document.write( "(2) \"+4+=+%28+5+-+w+%29%2At+\"
\n" ); document.write( "(2) \"+4+=+%28+5+-+2.895+%29%2A1.9+\"
\n" ); document.write( "(2) \"+4+=+2.105%2A1.9+\"
\n" ); document.write( "(2) \"+4+=+3.9995+\"
\n" ); document.write( "close enough
\n" ); document.write( "The wind speed is 2.895 mi/hr\r
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