document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=71238>Question 71238</A>: <I><SPAN STYLE=\"word-break: break-all;\"> John has 300 feet of lumber to frame a rectangular patio (the perimeter of a rectangle is 2 times length plus 2 times width). He wants to maximize the area of his patio (area of a rectangle is length times width). What should the dimensions of the patio be, and show how the maximum area of the patio is calculated from the algebraic equation.  \r<BR>\n" );
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document.write( "Show clearly the algebraic steps which prove your dimensions are the maximum area which can be obtained. Use the vertex formula to find the maximum area.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #50966 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=50966\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> THE MAXIMUM AREA OF ANY RECTANGLE IS A SQUARE. THUS:<BR>\n" );
document.write( "2X+2X=300<BR>\n" );
document.write( "4X=300<BR>\n" );
document.write( "X=300/4<BR>\n" );
document.write( "X=75 FEET PER SIDE.<BR>\n" );
document.write( "THIS ASSUMES THE PATIO IS A STAND-ALONE STRUCTURE.<BR>\n" );
document.write( "IF IT IS ATTACHED TO A HOUSE THEN THERE ARE ONLY THREE SIDES THAT NEEDS TO BE ENCLOSED. THUS THE SOLUTION HERE IS<BR>\n" );
document.write( "3X=300<BR>\n" );
document.write( "X=300/3<BR>\n" );
document.write( "X=100 FEET ON A SIDE.    </SPAN>\n" );
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