document.write( "Question 846211: A girl walked from her home to the fitness center at 6 km/h. She stayed at the gym for 45 min then got a ride home at 48 km/h. If she returned 1.5 hours after starting out, find the distance from the home to the fitness center. \n" ); document.write( "
Algebra.Com's Answer #509658 by josmiceli(19441)\"\" \"About 
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Let \"+d+\" = distance to fitness center
\n" ); document.write( "Let \"+t++\" = time to get there
\n" ); document.write( "\"+t+=+d%2F6+\" hrs
\n" ); document.write( "----------------------
\n" ); document.write( "\"+1.5+\" hrs = \"+90+\" min
\n" ); document.write( "\"+90+-+45+=+45+\"
\n" ); document.write( "Her time spent traveling is \"+45+\" min
\n" ); document.write( "or \"+3%2F4+\" hrs
\n" ); document.write( "----------------------
\n" ); document.write( "Her time coming home is:
\n" ); document.write( "\"+t+=+d%2F48+\" hrs
\n" ); document.write( "----------------------
\n" ); document.write( "\"+d%2F6+%2B+d%2F48+=+3%2F4+\"
\n" ); document.write( "Multiply both sides by \"+48+\"
\n" ); document.write( "\"+8d+%2B+d+=+36+\"
\n" ); document.write( "\"+9d+=+36+\"
\n" ); document.write( "\"+d+=+4+\"
\n" ); document.write( "the distance from the home to the fitness center
\n" ); document.write( "is 4 km
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