document.write( "Question 845902: A farmer needs to build a rectangular corral for his animals. He has 200 yards of fencing available. He needs to make 4 pens. What is the largest corral he can create? (Remember the pens also count as a part of the perimeter, not just the outside of the corral) \n" ); document.write( "
Algebra.Com's Answer #509594 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A farmer needs to build a rectangular corral for his animals. \n" ); document.write( " He has 200 yards of fencing available. \n" ); document.write( " He needs to make 4 pens. \n" ); document.write( " What is the largest corral he can create? \n" ); document.write( ": \n" ); document.write( "To make 4 pens he needs 4 times the width of the corral, therefore: \n" ); document.write( "2L + 4W = 200 \n" ); document.write( "Simplify, divide by 2 \n" ); document.write( "L + 2W = 100 \n" ); document.write( "L = (100-2W) \n" ); document.write( "Total area \n" ); document.write( "A = L * W \n" ); document.write( "replace L with (100-2W) \n" ); document.write( "A = (100-2W)*W \n" ); document.write( "A = -2W^2 + 100W \n" ); document.write( "A quadratic equation, max area occurs at the axis of symmetry; x = -b/(2a) \n" ); document.write( "W = \n" ); document.write( "W = +25 yds is the width that gives max area \n" ); document.write( "Find Length \n" ); document.write( "L = 100 - 2(25) \n" ); document.write( "L = 50 yds length for max area \n" ); document.write( "Find max area \n" ); document.write( "50 * 25 = 1250 sq/yds \n" ); document.write( " |