document.write( "Question 845977: How many liters of a 50% acid solution must be added to 16 liters of a 30% acid solution to produce a 35% acid solution?\r
\n" ); document.write( "\n" ); document.write( "I put (.50)(L)+ (.30)(16)=.35(16+L)
\n" ); document.write( "multiplied each by 100
\n" ); document.write( "50L + 48000 = 560 + 35L
\n" ); document.write( "50L - 35L + 4800 = 560
\n" ); document.write( "15L + 4800 = 560
\n" ); document.write( "15L = -4240
\n" ); document.write( "L = -282.6\r
\n" ); document.write( "\n" ); document.write( "I know I am way off and need assistance. \n" ); document.write( "
Algebra.Com's Answer #509514 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
Your initial equation is fine
\n" ); document.write( "(.50)(L)+ (.30)(16)=.35(16+L)
\n" ); document.write( "You messed up multiplying by 100
\n" ); document.write( "50L + 30*16 = 35*16 + 35L
\n" ); document.write( "50L + 480 = 560 + 35L
\n" ); document.write( "15L=80
\n" ); document.write( "L=80/15
\n" ); document.write( "L=5 1/3=5.33333\r
\n" ); document.write( "\n" ); document.write( "without multiplying by 100
\n" ); document.write( "(.50)(L)+ (.30)(16)=.35(16+L)
\n" ); document.write( ".50L+ 4.8=5.6+.35L
\n" ); document.write( "0.15 L=0.80
\n" ); document.write( "L=.80/.15
\n" ); document.write( "L = 5.33333
\n" ); document.write( " \n" ); document.write( "
\n" );