document.write( "Question 845913: Kurt is now three times as old as Jason. Three years from now, Kurt will be six times as old as Jason one year ago. Find their present ages.
\n" ); document.write( " \n" ); document.write( "

Algebra.Com's Answer #509510 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
1. $\"K=3J\"$
\n" ); document.write( "2. $\"K%2B3=6%28J-1%29\"$
\n" ); document.write( "Substitute eq. 1 into eq. 2,
\n" ); document.write( " $\"3J%2B3=6J-6\"$
\n" ); document.write( " $\"3J=9\"$
\n" ); document.write( " $\"J=3\"$
\n" ); document.write( "Then from eq. 1,
\n" ); document.write( " $\"K=3J=3%283%29=9\"$ \r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );