document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=845853>Question 845853</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the linear system using substitution.<BR>\n" );
document.write( "2x=12<BR>\n" );
document.write( "x-5y=-29<BR>\n" );
document.write( "help? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #509472 by </B><A HREF=/tutors/aboutme.mpl?userid=pmesler><B>pmesler(52)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=pmesler><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=pmesler><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=509472\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Right away we can see that equation 1 evaluates to x = 6. Since we know that we can substitute that value into equation 2.\r<BR>\n" );
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document.write( "2-5y=-29\r<BR>\n" );
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document.write( "Now solve for y.\r<BR>\n" );
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document.write( "Subtract 2 from both sides.\r<BR>\n" );
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document.write( "-5y = -35\r<BR>\n" );
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document.write( "Divide each side by -5\r<BR>\n" );
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document.write( "y = 7\r<BR>\n" );
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document.write( "Therefore the solution is x = 6 y = 7\r<BR>\n" );
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document.write( " </SPAN>\n" );
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