document.write( "Question 845641: There are 3 parts to this questions. I have been stuck on this question for a long time. PLEASE HELP!!\r
\n" ); document.write( "\n" ); document.write( "A storage tank contains a radioactive element with a half-life of 6500 years. Let f(t) be the percentage of the element that remains at t years since it was placed in the tank.\r
\n" ); document.write( "\n" ); document.write( "Question A: Find an equation of f.
\n" ); document.write( "Question B: What percentage of the element will remain after 100 years?
\n" ); document.write( "Question C: What percentage of the element remains after 26,000 years? [NOTE: this result could be found using the equation of f, but we'll use a different approach to find the percentage].\r
\n" ); document.write( "\n" ); document.write( "PLEASE HELP ME SOLVE THIS PROBLEM!!! and PLEASE SHOW WORK SO I CAN UNDERSTAND IT!\r
\n" ); document.write( "\n" ); document.write( "Thanks!!
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Algebra.Com's Answer #509460 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
A After one half-life the fraction of the element that remains is \"1%2F2\" .
\n" ); document.write( "After \"2\" half-lives the fraction of the element that remains is \"1%2F2\" of \"1%2F2\" , which is \"%281%2F2%29%2A%281%2F2%29=%281%2F2%29%5E2\" .
\n" ); document.write( "After \"3\" half-lives the fraction of the element that remains is \"%281%2F2%29%5E3\" .
\n" ); document.write( "The same idea works for any number of half-lives, even if that number is not an integer.
\n" ); document.write( "\"t\" years is \"t%2F6500\" half-lives,
\n" ); document.write( "After that time, the fraction of the element that remains is
\n" ); document.write( "\"%281%2F2%29%5E%22t+%2F+6500%22\"
\n" ); document.write( "As a percentage, it is \"f%28t%29=100%2A%281%2F2%29%5E%22t+%2F+6500%22\" .
\n" ); document.write( "That is an exponential function with base \"1%2F2\" , and that is not a fashionable base.
\n" ); document.write( "Calculators have exponential functions with base \"10\" and with base \"e\" .
\n" ); document.write( "The most popular base for exponential functions is the irrational number \"e\" .
\n" ); document.write( "The reason for that is that calculus works better with \"e\" as a base,
\n" ); document.write( "so even if you do not intend to ever study calculus, they make you use \"e\" rather than \"10\" .
\n" ); document.write( "It is customary to write the function as
\n" ); document.write( "\"f%28t%29=100%2Ae%5E%28%22-+ln+%28+2+%29+%2A+t+%2F+6500%22%29\" or \"f%28t%29=100%2Ae%5E%28%22-+0.693%2At+%2F+6500%22%29\" .
\n" ); document.write( "It is really the same thing, because the natural logarithm of \"%281%2F2%29%5E%22t+%2F+6500%22\" is
\n" ); document.write( "\"%28t%2F6500%29%2Aln%281%2F2%29=%28t%2F6500%29%2A%28-ln%282%29%29=-ln%282%29%2At%2F6500\" .
\n" ); document.write( "People memorize the \"formula\" for the exponential function with base \"e\" without understanding it.
\n" ); document.write( "I never memorized that formula, but I can deduce the one with \"1%2F2\" as a base from the definition of half-life, and then I can \"translate\" it to base \"e\" .
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\n" ); document.write( "B When \"t=100\" , \"-0.693%2At%2F6500=-69.3%2F6500\" and
\n" ); document.write( "\"f%28t%29=100%2Ae%5E%28%22-69.3+%2F+6500%22%29=100%2A0.989=98.9\"
\n" ); document.write( "So after 100 years 98.9% of the radioactive element remains.
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\n" ); document.write( "C \"26000%2F6500=4\" so 26,000 years is \"4\" half-lives.
\n" ); document.write( "The fraction that remains after \"4\" half-lives is
\n" ); document.write( "\"%281%2F2%29%5E4=1%2F16=0.0625\" That is 6.25% .
\n" ); document.write( "No formula used. We do not need \"e\" for that.
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