document.write( "Question 845794: How do I solve for X
\n" ); document.write( "5^2x+7=9
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Algebra.Com's Answer #509459 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
If the equation is \"5%5E%282x%2B7%29=9\", then...\r
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\n" ); document.write( "\n" ); document.write( "\"5%5E%282x%2B7%29=9\"\r
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\n" ); document.write( "\n" ); document.write( "\"2x%2B7=log%285%2C%289%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"2x=log%285%2C%289%29%29-7\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28log%285%2C%289%29%29-7%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "OR...If the equation is \"5%5E%282x%29%2B7=9\", then...\r
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\n" ); document.write( "\n" ); document.write( "\"5%5E%282x%29%2B7=9\"\r
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\n" ); document.write( "\n" ); document.write( "\"5%5E%282x%29=9-7\"\r
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\n" ); document.write( "\n" ); document.write( "\"5%5E%282x%29=2\"\r
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\n" ); document.write( "\n" ); document.write( "\"2x=log%285%2C%282%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"2x=log%285%2C%282%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28log%285%2C%282%29%29%29%2F2\"
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