document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=845424>Question 845424</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve the equation 3cos A + 2sin A = 2.8 for 0 degrees<A<360 degrees </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #509322 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=509322\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  solve the equation 3cos A + 2sin A = 2.8<BR>\n" );
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document.write( "3cos(A) + 2sqrt(1-cos^2(A)) = 2.8<BR>\n" );
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document.write( "2sqrt(1-cos^2(A)) = 2.8-3cos(A)<BR>\n" );
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document.write( "Square both sides to get:<BR>\n" );
document.write( "4-4cos^2(A)) = 2.8^2 - 16.8cosA + 9cos^2(A)<BR>\n" );
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document.write( "13cos^2(A) - 16.8cos(A) + 3.84 = 0<BR>\n" );
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document.write( "cos(A) = [16.8 +- sqrt(16.8^2 -4*9*3.84)]/26<BR>\n" );
document.write( "cos(A) = [16.8+-12]/26<BR>\n" );
document.write( "cos(A) = 4.8/26 = 0.1846<BR>\n" );
document.write( "A = arccos(0.1846) = 79.36 degrees<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "==============<BR>\n" );
document.write( " </SPAN>\n" );
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