document.write( "Question 845367: the area of a rectangle is 56 and its perimeter is 30. find the difference of its length and width \n" ); document.write( "
Algebra.Com's Answer #509268 by hamsanash1981@gmail.com(151)\"\" \"About 
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area = 56
\n" ); document.write( "l*b = 56
\n" ); document.write( "perimeter = 30
\n" ); document.write( "2(l+b) = 30
\n" ); document.write( "l+b = 15
\n" ); document.write( "squaring on both sides
\n" ); document.write( "(l+b)^2 = 225
\n" ); document.write( "\"l%5E2%2Bb%5E2+%2B+2lb+=+225\"
\n" ); document.write( "\"a%5E2%2Bb%5E2+=+%28%28a%2Bb%29%5E2+%2B+%28a-b%29%5E2%29%2F2\"
\n" ); document.write( "\"%28%28l%2Bb%29%5E2+%2B%28l-b%29%5E2%29%2F2+%2B2lb=+225\"
\n" ); document.write( "\"%28%2815%29%5E2%2B+%28l-b%29%5E2+%2B+4%2A56%29%2F2+=225\"
\n" ); document.write( "\"225%2B%28l-b%29%5E2+%2B+224+=450\"
\n" ); document.write( "\"%28l-b%29%5E2%2B+449+=+450\"
\n" ); document.write( "\"%28l-b%29%5E2+=1\"
\n" ); document.write( "\"l-b+=+1\"
\n" ); document.write( "
\n" );