document.write( "Question 71190: The length of a rectangle is 8 in. more than twice its width. If the perimeter of the rectangle is 64 in., find the width of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #50926 by checkley75(3666)\"\" \"About 
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L=8+2W
\n" ); document.write( "64=2(8+2W)+2W
\n" ); document.write( "64=16+4W+2W
\n" ); document.write( "64-16=6W
\n" ); document.write( "48=6W
\n" ); document.write( "48/6=W
\n" ); document.write( "8=W ANSWER FOR THE WIDTH
\n" ); document.write( "PROOF
\n" ); document.write( "64=2(8+2*8)+2*8
\n" ); document.write( "64=2(8+16)+16
\n" ); document.write( "64=2*24+16
\n" ); document.write( "64=48+16
\n" ); document.write( "64=64\r
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