document.write( "Question 845367: the area of a rectangle is 56 and its perimeter is 30. find the difference of its length and width \n" ); document.write( "
Algebra.Com's Answer #509251 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! x and y are the dimensions, one of them length and the other width.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Area description means xy=56 and perimeter description means 2x+2y=30. For just solving the problem asked, solving for x and y is more important and would be done first.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The perimeter equation is easily simplified to x+y=15. This also directly gives y=15-x and can be substituted....\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "- \n" ); document.write( "Easily mentally skipping steps, the difference between the length and width is ONE UNIT. \n" ); document.write( "- \n" ); document.write( "In case one could not skip the steps, then continuing form the factored quadratic equation, either x=7 or x=8. \n" ); document.write( "Using area equation xy=56, find that y=56/x. \n" ); document.write( "That means either y=56/7=8 or y=56/8=7. \n" ); document.write( "Either way, the difference between x and y is 1. \n" ); document.write( " |