document.write( "Question 71190: The length of a rectangle is 8 in. more than twice its width. If the perimeter of the rectangle is 64 in., find the width of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #50925 by hailu(13)\"\" \"About 
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L=8+2W
\n" ); document.write( "(L+W)2=64
\n" ); document.write( "W=?
\n" ); document.write( "substitute for (L)
\n" ); document.write( "(8+2W+W)2=64
\n" ); document.write( "(8+3W)2=64
\n" ); document.write( "16+6W=64
\n" ); document.write( "6W=64-16
\n" ); document.write( "6W=48
\n" ); document.write( "W=48/6
\n" ); document.write( "W=8
\n" ); document.write( "width is 8\r
\n" ); document.write( "\n" ); document.write( "therefore (L) is
\n" ); document.write( "L=8+2(8)
\n" ); document.write( "L=8+16
\n" ); document.write( "L=24
\n" ); document.write( "
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