document.write( "Question 71190: The length of a rectangle is 8 in. more than twice its width. If the perimeter of the rectangle is 64 in., find the width of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #50925 by hailu(13)![]() ![]() ![]() You can put this solution on YOUR website! L=8+2W \n" ); document.write( "(L+W)2=64 \n" ); document.write( "W=? \n" ); document.write( "substitute for (L) \n" ); document.write( "(8+2W+W)2=64 \n" ); document.write( "(8+3W)2=64 \n" ); document.write( "16+6W=64 \n" ); document.write( "6W=64-16 \n" ); document.write( "6W=48 \n" ); document.write( "W=48/6 \n" ); document.write( "W=8 \n" ); document.write( "width is 8\r \n" ); document.write( "\n" ); document.write( "therefore (L) is \n" ); document.write( "L=8+2(8) \n" ); document.write( "L=8+16 \n" ); document.write( "L=24 \n" ); document.write( " \n" ); document.write( " |