document.write( "Question 845350: solve the inequality algebraically.
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document.write( "so confused on this section.\r
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document.write( "2x^2+13x+6<0 \n" );
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Algebra.Com's Answer #509240 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 2x^2+13x+6<0 \n" ); document.write( "----- \n" ); document.write( "Factor: \n" ); document.write( "2x^2 + 12x+x + 6 < 0 \n" ); document.write( "Factor: \n" ); document.write( "2x(x+6)+(x+6) < 0 \n" ); document.write( "Factor: \n" ); document.write( "(x+6)(2x+1) < 0 \n" ); document.write( "------- \n" ); document.write( "Draw a number and plot x = -6 and x = -1/2 \n" ); document.write( "Note: These are value x CANNOT take:: \n" ); document.write( "Check the three segments of the number line to find valid solutions:: \n" ); document.write( "(x+6)(2x+1) < 0 \n" ); document.write( "--- \n" ); document.write( "Note: I use the + and - because you only want to know if the \n" ); document.write( "product is less than zero. \n" ); document.write( "If x = -10 you get:: -*- < 0 which is false \n" ); document.write( "If x = -3 you get:: +*- < 0 which is true \n" ); document.write( "If x = 0 you get:: +*+ < 0 which is false \n" ); document.write( "------ \n" ); document.write( "Solution set:: -6 < x < -1/2 or (-6,-1/2) \n" ); document.write( "----------------------------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================= \n" ); document.write( " |