document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=845311>Question 845311</A>: <I><SPAN STYLE=\"word-break: break-all;\"> when 25 is added to a number and the result is halved, the answer is 3 times the original number. what is the number? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #509228 by </B><A HREF=/tutors/aboutme.mpl?userid=pmesler><B>pmesler(52)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=pmesler><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=pmesler><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=509228\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = the number.<BR>\n" );
document.write( "The wording in the question is a little tricky, but if you read it carefully it just says to add 25 to a number x. The result will be 3 times that number and then halved. That's the simple way of restating the problem. Mathematically we can write it like this:\r<BR>\n" );
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document.write( "x + 25 = 3x/2. Now we just solve for x.\r<BR>\n" );
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document.write( "We start by subtracting x from both sides since 1 is less than 3/2.\r<BR>\n" );
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document.write( "we get 25 = 1/2x\r<BR>\n" );
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document.write( "To solve for x we need to multiply each side by the reciprocal of 1/2 which is 2/1 or 2. We do this so the numerator and denominators divide out and you're just left with x. \r<BR>\n" );
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document.write( " (2)25 = (1/2x)(2)\r<BR>\n" );
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document.write( "50 = x \r<BR>\n" );
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document.write( "Therefore the number is 50. Let's check to see if that's correct. We do this by substituting 50 into the original equation like this:\r<BR>\n" );
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document.write( "50 + 25 = 3/2(50)\r<BR>\n" );
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document.write( "75 = 150/2\r<BR>\n" );
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document.write( "75 = 75. It checks out so x = 50 is the correct answer.  </SPAN>\n" );
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