document.write( "Question 844903: two friends live 2.1 mi apart along the same road. If they walk toward each other at rates that diff by 1/2 mph and meet 36mins later how fast was each person walking? \n" ); document.write( "
Algebra.Com's Answer #509224 by ankor@dixie-net.com(22740)\"\" \"About 
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two friends live 2.1 mi apart along the same road.
\n" ); document.write( " If they walk toward each other at rates that diff by 1/2 mph and meet 36mins later
\n" ); document.write( " how fast was each person walking?
\n" ); document.write( ":
\n" ); document.write( "Let w = walking speed of the slower guy
\n" ); document.write( "then
\n" ); document.write( "(w+.5) = walking speed of the faster guy
\n" ); document.write( ":
\n" ); document.write( "Since we a working in mph, change 36 min: 36/60 = .6 hrs
\n" ); document.write( ":
\n" ); document.write( "When they meet their total distances will equal 2.1 mi
\n" ); document.write( ":
\n" ); document.write( "Write a distance equation, dist = speed * time
\n" ); document.write( ".6w + .6(w+.5) = 2.1
\n" ); document.write( ".6w + .6w + .3 = 2.1
\n" ); document.write( "1.2w = 2.1 - .3
\n" ); document.write( "w = 1.8/1.2
\n" ); document.write( "w = 1.5 mph for the slow guy
\n" ); document.write( "and
\n" ); document.write( "2.0 mph for the speedster
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Confirm this solution by finding the actual dist each walked
\n" ); document.write( "1.5*.6 = .9
\n" ); document.write( "2.0*.6 = 1.2
\n" ); document.write( "-------------
\n" ); document.write( "total: 2.1 \n" ); document.write( "
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