document.write( "Question 844558: The length of a rectangle is 11 more than twice its width. The perimeter of the rectangle is 118 feet. Find the dimensions of the rectangle \n" ); document.write( "

Algebra.Com's Answer #509222 by hamsanash1981@gmail.com(151) $\"\"$ $\"About$

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let the width be x, then length = 2x+11
\n" ); document.write( "perimeter = 118
\n" ); document.write( "2(2X+11+X) =118
\n" ); document.write( "3X+11 = 59
\n" ); document.write( "3x = 48
\n" ); document.write( "x = 16
\n" ); document.write( "width = 16
\n" ); document.write( "length = 2(16)+11 = 43
\n" ); document.write( "the dimension of the rectangle = 43*16 \n" ); document.write( "

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