document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=845263>Question 845263</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the equation:\r<BR>\n" );
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document.write( "(2m+4)^(1/7)-(m-3)^(1/7)=0\r<BR>\n" );
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document.write( "The Solution set is______.\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #509206 by </B><A HREF=/tutors/aboutme.mpl?userid=pmesler><B>pmesler(52)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=pmesler><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=pmesler><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=509206\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First, let's review some basic algebra principles. We know that \r<BR>\n" );
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document.write( "a^1/n = nth root (a) \r<BR>\n" );
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document.write( "For example, a^1/2 = sqrt(a).\r<BR>\n" );
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document.write( "So, we can rewrite this equation like this:\r<BR>\n" );
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document.write( "7throot(2m+4) - 7throot(m-3) = 0\r<BR>\n" );
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document.write( "Now, to get rid of roots, we simply need to raise the expression to the same power as the root, in this case 7. \r<BR>\n" );
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document.write( "(7throot(2m+4))^7 - (7throot(m-3))^7 = (0)^7.\r<BR>\n" );
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document.write( "We are then left with \r<BR>\n" );
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document.write( "2m+4 - m - 3 = 0\r<BR>\n" );
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document.write( "Now let's solve for m.\r<BR>\n" );
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document.write( "Combine like terms\r<BR>\n" );
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document.write( "(2m)-m + 4 - 3 = 0\r<BR>\n" );
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document.write( " and we are left with\r<BR>\n" );
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document.write( "m + 1 = 0. \r<BR>\n" );
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document.write( "Therefore m = -1.  </SPAN>\n" );
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