document.write( "Question 845134: How do you solve 2x^2-8=0 using the quadratic formula? \n" ); document.write( "
Algebra.Com's Answer #509150 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
\"+2x%5E2+-+8+=+0+\"
\n" ); document.write( "\"+x+=+%28+-b+%2B-+sqrt%28+b%5E2+-+4%2Aa%2Ac+%29%29+%2F+%282%2Aa%29+\"
\n" ); document.write( "\"+a+=+2+\"
\n" ); document.write( "\"+b+=+0+\"
\n" ); document.write( "\"+c+=+-8+\"
\n" ); document.write( "\"+x+=+%28+-0+%2B-+sqrt%28+0%5E2+-+4%2A2%2A%28-8%29+%29%29+%2F+%282%2A2%29+\"
\n" ); document.write( "\"+x+=+%28+-0+%2B-+sqrt%28+64+%29%29+%2F+4+\"
\n" ); document.write( "\"+x+=+8%2F4+\"
\n" ); document.write( "\"+x+=+2+\"
\n" ); document.write( "and, also:
\n" ); document.write( "\"+x+=+-8%2F4+\"
\n" ); document.write( "\"+x+=+-2+\"
\n" ); document.write( "Here's a plot showing roots \"+x+=+2+\", and \"+x+=+-2+\"
\n" ); document.write( "\"+graph%28+400%2C+400%2C+-5%2C+5%2C+-10%2C+5%2C+2x%5E2+-+8+%29+\"\r
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