document.write( "Question 71210: given the equation y=-5x+1\r
\n" ); document.write( "\n" ); document.write( "a. find the slope of a line parallel
\n" ); document.write( "b. find the slope of a line perpendicular
\n" ); document.write( "c. graph a parallel line that goes throught the point (4,-1)
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Algebra.Com's Answer #50906 by checkley75(3666)\"\" \"About 
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y=-5x+1 is the formula for a line with as slope of (-5).
\n" ); document.write( "A) Any line with a slope of (-5) is parallel to this line
\n" ); document.write( "B) Any line perpendicular to this line has a slope of the negative recoprical of this slope. Thus (+1/5) is the slopre of any perpendicular line.
\n" ); document.write( "C) a parallel line through (4,1) with a slope of (-5)is:
\n" ); document.write( "-1=-5*4+b
\n" ); document.write( "-1=-20+b
\n" ); document.write( "-1+20=b
\n" ); document.write( "b=19 so the formula for this line is:
\n" ); document.write( "y=-5x+19\r
\n" ); document.write( "\n" ); document.write( "\"+graph%28+400%2C+400%2C+-20%2C+20%2C+-20%2C+20%2C+y+=+-5x+%2B19%29+\" (graph 400x400 pixels, x 4from -20 to 20, y from -20 to 20, y = -5x +19).
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