document.write( "Question 71163This question is from textbook
\n" ); document.write( ": Solve the eqqation
\n" ); document.write( "(y/5)-(2/5)=(1/3)-y
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Algebra.Com's Answer #50905 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
Solve the eqqation \r
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\n" ); document.write( "\n" ); document.write( "(y/5)-(2/5)=(1/3)-y\r
\n" ); document.write( "\n" ); document.write( "First, lets get rid of the fractions by multiplying every term by 15, the LCM\r
\n" ); document.write( "\n" ); document.write( "\"%28y%2F5%29%2815%29-%282%2F5%29%2815%29=%281%2F3%29%2815%29-y%2815%29\" simplify \r
\n" ); document.write( "\n" ); document.write( "\"3y-6=5-15y\" subtract 3y and also 5 from both sides\r
\n" ); document.write( "\n" ); document.write( "\"3y-3y-6-5=5-5-15y-3y\" collect like terms\r
\n" ); document.write( "\n" ); document.write( "\"-11=-18y\" divide both sides by -18\r
\n" ); document.write( "\n" ); document.write( "\"y=11%2F18\" or
\n" ); document.write( "\"y=0.6111\"\r
\n" ); document.write( "\n" ); document.write( "ck ----------plug y=0.6111 into original equation\r
\n" ); document.write( "\n" ); document.write( "\"%280.6111%2F5%29-0.4=0.3333-0.6111\"
\n" ); document.write( "\"0.12222-0.4=0.3333-0.6111\"\r
\n" ); document.write( "\n" ); document.write( "\"-0.27778=-0.27778\"\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor\r
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