document.write( "Question 9376: If xy=-3 and x2+ y2=12 then (x-y)2=?
\n" ); document.write( "note: the \"2\" behind the varibles mean squared. and the (x-y)2 means squared.
\n" ); document.write( "thanks
\n" ); document.write( "Dean
\n" ); document.write( "xy=-3
\n" ); document.write( "2xy=-6
\n" ); document.write( "x2+y2=12
\n" ); document.write( "x2+y2-2xy=12-2xy
\n" ); document.write( "(x-y)2=12-*-6
\n" ); document.write( "(x-y)2=12+12
\n" ); document.write( "(x-y)2=24 \n" ); document.write( "

Algebra.Com's Answer #5090 by jawaidak(3) $\"\"$ $\"About$

You can put this solution on YOUR website!
xy=-3
\n" ); document.write( "2xy=-6
\n" ); document.write( "x2+y2=12
\n" ); document.write( "x2+y2-2xy=12-2xy
\n" ); document.write( "(x-y)2=12-2*-3
\n" ); document.write( "(x-y)2=12+6
\n" ); document.write( "(x-y)2=18 \n" ); document.write( "

\n" );