document.write( "Question 844908: A class contains 8 boys and 14 girls. Two students are to be selected as student council representatives. What is the probability both are boys? \n" ); document.write( "
Algebra.Com's Answer #508990 by Theo(13342)\"\" \"About 
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there are 8 boys and 14 girls.
\n" ); document.write( "you will be selecting 2 out of the 22 total.
\n" ); document.write( "the number of ways that can occur is 22C2 = 231.
\n" ); document.write( "the number of ways you can select 2 boys out of a total of 8 boys is 8C2 = 28
\n" ); document.write( "the probability that you will select 2 boys is the number of ways you can select 2 boys out of 8 divided by the number of ways you can select 2 students out of 22.
\n" ); document.write( "that probability would be equal to 28 / 231 = .12 rounded to 2 decimal places.\r
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\n" ); document.write( "\n" ); document.write( "let's look at it another way.
\n" ); document.write( "the probability that the first pick will be a boy is 8/22.
\n" ); document.write( "the probability that the second pick will also be a boy is 7/21
\n" ); document.write( "the probability that both will be a boy is 8/22 * 7/21 which is equal to 56 / 462 which is equivalent to 28 / 231.\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "the decimal equivalent to this is .12 rounded to 2 decimal places.
\n" ); document.write( "the simplest fraction will be 4/33 since both 28 and 231 are divisible by 7.\r
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\n" ); document.write( "\n" ); document.write( "22C2 is equal to 22! / (2! * 20!)
\n" ); document.write( "8C2 is equal to 8! / (2! * 6!)
\n" ); document.write( "the general combination equation is:
\n" ); document.write( "nCx = n! / (x! * (n-x)!)\r
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\n" ); document.write( "\n" ); document.write( "the best way to see this is to use much smaller numbers so you can identify each possible combination.
\n" ); document.write( "assume 3 boys and 2 girls and you pick a team of 2 and you want to know the probability that you will pick 2 boys.
\n" ); document.write( "assuming boys are letters and girls are number, you will get the following possible combinations of 2 students.
\n" ); document.write( "ab
\n" ); document.write( "ac
\n" ); document.write( "a1
\n" ); document.write( "a2
\n" ); document.write( "bc
\n" ); document.write( "b1
\n" ); document.write( "b2
\n" ); document.write( "c1
\n" ); document.write( "c2
\n" ); document.write( "12
\n" ); document.write( "that's a total of 10 possible combinations of 2 students.
\n" ); document.write( "out of those 10 possible combinations, 3 are all boys.
\n" ); document.write( "they are:
\n" ); document.write( "ab
\n" ); document.write( "ac
\n" ); document.write( "bc
\n" ); document.write( "the rest are either boy and girl or all girl.\r
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\n" ); document.write( "\n" ); document.write( "the formulas you would use in this simplified example are:\r
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\n" ); document.write( "\n" ); document.write( "3C2 / 5C2 which results in 3/10.
\n" ); document.write( "3/5 * 2/4 which results in 6/20 which results in 3/10.\r
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\n" ); document.write( "\n" ); document.write( "either method results in the same probability as it should.\r
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