document.write( "Question 844890: How much pure acid should be mixed with 4 gallons of a 50% acid solution in order to get an 80% acid solution? \n" ); document.write( "
Algebra.Com's Answer #508977 by josgarithmetic(39617)\"\" \"About 
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Just with that information, we could expect the percents to be as w/v.\r
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\n" ); document.write( "\n" ); document.write( "Let v = how much volume of the pure acid to add\r
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\n" ); document.write( "\n" ); document.write( "\"%2850%2A4%2B100v%29%2F%28v%2B4%29=80\"
\n" ); document.write( "Solve for v\r
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\n" ); document.write( "\n" ); document.write( "Study this lesson to understand better:
\n" ); document.write( "http://www.algebra.com/tutors/Two-Part-Mixture-with-one-material-quantity-unknown.lesson?content_action=show_dev
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