document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=71214>Question 71214</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/067345956x/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> I have a problem that I can't figure out.  If the perimeter of a square is 16s+24, find the area.  I keep coming up with an answer that I know just be right.Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #50896 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=50896\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  have a problem that I can't figure out. If the perimeter of a square is 16s+24, find the area.<BR>\n" );
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document.write( "You know that the side of a square is 1/4 the perimeter, right?<BR>\n" );
document.write( "(1/4)*(16s + 24) = (4s + 6)<BR>\n" );
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document.write( "Area =(4s + 6)^2 <BR>\n" );
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document.write( "FOIL (4s +6)(4s + 6) and you have:<BR>\n" );
document.write( "16s^2 + 24s + 24s + 36<BR>\n" );
document.write( "Which is:<BR>\n" );
document.write( "16s^2 + 48s + 36 </SPAN>\n" );
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