document.write( "Question 843988: How many liters of 10% acid solution should be added to 20 liters of 60% solution of acid to obtain a 50% solution? \n" ); document.write( "
Algebra.Com's Answer #508951 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
.1x+.6*20=(20+x)*.5
\n" ); document.write( "x/10+3/5*20=10+x/2
\n" ); document.write( "x/10+12=10+x/2\r
\n" ); document.write( "\n" ); document.write( "x/10+2=x/2
\n" ); document.write( "x/10+2=5x/10
\n" ); document.write( "2=4x/10
\n" ); document.write( "20=4x
\n" ); document.write( "5=x
\n" ); document.write( "check
\n" ); document.write( ".5+12=25/2
\n" ); document.write( "12.5-=12.5
\n" ); document.write( "ok\r
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