document.write( "Question 844729: Describe the vertical asymptote(s) and hole(s) for the graph of y=(x+2)(x+4)/(x+4)(x+1). \n" ); document.write( "
Algebra.Com's Answer #508914 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
For \"x=-4\" , \"y=%28x%2B2%29%28x%2B4%29%2F%28%28x%2B4%29%28x%2B1%29%29\" does not exist, because the denominator is zero.
\n" ); document.write( "However, for any \"x%3C%3E-4\" ,
\n" ); document.write( "\"y=%28x%2B2%29%28x%2B4%29%2F%28%28x%2B4%29%28x%2B1%29%29=%28x%2B2%29%2F%28x%2B1%29\" which is continuous at \"x=-4\" .
\n" ); document.write( "So, at \"x=-4\" we have a hole in the graph.
\n" ); document.write( "The function \"y=%28x%2B2%29%2F%28x%2B1%29\" is what results from \"plugging\" that hole.
\n" ); document.write( "For \"x=-1\" , \"y=%28x%2B2%29%28x%2B4%29%2F%28%28x%2B4%29%28x%2B1%29%29\" does not exist, and there is no equivalent continuous function. (No plugging possible).
\n" ); document.write( "At \"x=-1\", the functions \"y=%28x%2B2%29%28x%2B4%29%2F%28%28x%2B4%29%28x%2B1%29%29\" and \"y=%28x%2B2%29%2F%28x%2B1%29\" have a vertical asymptote.
\n" ); document.write( "The function changes sign at that point.
\n" ); document.write( "\"y=%28x%2B2%29%2F%28x%2B1%29\" is positive for \"x%3E-1\" , where \"x%2B1%3E0\" and \"x%2B2%3E0\" .
\n" ); document.write( "It is negative for \"-2%3Cx%3C-1\" , where \"x%2B1%3C0\" and \"x%2B2%3E0\" .
\n" ); document.write( "\"graph%28300%2C300%2C-6%2C4%2C-10%2C10%2C%28x%2B2%29%2F%28x%2B1%29%2C200%28x%2B1%29%29\"
\n" ); document.write( "
\n" );