document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=71137>Question 71137</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Heyy i really need some help on this question.. give me a hand pleasee.\r<BR>\n" );
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document.write( "In a circle with radius 7cm, a chord is 3cm from the center. How long is another chord located 3 cm from the center?\r<BR>\n" );
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document.write( "Those are the choice of answers, could you please give me the steps of how to do it please!\r<BR>\n" );
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document.write( "A) 2 (root)10<BR>\n" );
document.write( "B)7<BR>\n" );
document.write( "C)4 (root)10<BR>\n" );
document.write( "D)14\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #50887 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=50887\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Well, if I could draw the diagram it would be a whole easier, but I'll try to explain it in words so that you can draw the diagram:<BR>\n" );
document.write( "1. Draw the circle a radius of 7 cm.<BR>\n" );
document.write( "2. Mark a point 3 cm from the centre of the circle and draw a chord through it.<BR>\n" );
document.write( "3. Connect the end-points of the chords with the centre of the circle.<BR>\n" );
document.write( "You should now have an isosceles triangle inside the circle. The two equal sides of the triangle are just the radii of the circle so they are 7 cm. each and the base is just the diameter of the circle and that is 14 cm.<BR>\n" );
document.write( "4. Draw a line from the centre of the circle perpendicular to the chord.<BR>\n" );
document.write( "You should now see two congruent right triangles.<BR>\n" );
document.write( "Focus on one of these.  The height is 3 cm. and the hypotenuse is 7 cm. and the base is half the length of the chord.<BR>\n" );
document.write( "Using the Pythagorean theorem, you can find the third side (call this x) of one of the right triangles.<BR>\n" );
document.write( "x is one half the length of the chord so you will multiply this by 2 to get the entire length of the chord.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=7%5E2+=+3%5E2+%2B+x%5E2 ALIGN=MIDDLE  ALT=\"7%5E2+=+3%5E2+%2B+x%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Simplify and solve for x.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=49+=+9%2Bx%5E2 ALIGN=MIDDLE  ALT=\"49+=+9%2Bx%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Subtract 9 from both sides.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=40+=+x%5E2 ALIGN=MIDDLE  ALT=\"40+=+x%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Take the square root of both sides.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+sqrt%2840%29 ALIGN=MIDDLE  ALT=\"x+=+sqrt%2840%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > This is half the length of the chord.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x+=+2sqrt%2840%29 ALIGN=MIDDLE  ALT=\"2x+=+2sqrt%2840%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > This is the length of the chord. Simplifying this, you gey:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x+=+2sqrt%284%2A10%29 ALIGN=MIDDLE  ALT=\"2x+=+2sqrt%284%2A10%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > Take the sqrt of 4 outside the radical as 2.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x+=+4sqrt%2810%29 ALIGN=MIDDLE  ALT=\"2x+=+4sqrt%2810%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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