document.write( "Question 844111: Without using a calculator, test each of the following
\n" ); document.write( "numbers for divisibility by 2, 3, 4, 5, 6, 8, 9, 10, and 11:
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Algebra.Com's Answer #508807 by Fombitz(32388)\"\" \"About 
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2 - last digit divisible by 2.
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\n" ); document.write( "4 - last 2 digits divisible by 4
\n" ); document.write( "5 - ends in 5 or 0
\n" ); document.write( "6 - divisible by 2 and 3
\n" ); document.write( "8 - last 3 digits divisible by 8?
\n" ); document.write( "9 - Add the digits, the sum must be divisible by 9.
\n" ); document.write( "10 - last digit is 0.
\n" ); document.write( "11 - Add the odd positions starting from left to right. Add the even positions starting from left to right. If the difference of the sums is zero or a multiple of 11, the number is divisible by 11.
\n" ); document.write( "a) 2, yes
\n" ); document.write( "3, no, sum is 10
\n" ); document.write( "4, yes, 12/4=3
\n" ); document.write( "5, no
\n" ); document.write( "6, no
\n" ); document.write( "8, no
\n" ); document.write( "9, no
\n" ); document.write( "10, no
\n" ); document.write( "11, no, difference in sums is (4+0+0+2)-(2+1+1)=6-4=2\r
\n" ); document.write( "\n" ); document.write( "Now do the same for b and c.
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