document.write( "Question 71157This question is from textbook algebra
\n" ); document.write( ": 10y^2+9y+2 i cannot find anyone to help me with this whole problem factoring polynomials can ;you help me p;ease? thanks \n" ); document.write( "
Algebra.Com's Answer #50879 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Let's try the following.
\n" ); document.write( "Factor:
\n" ); document.write( "\"10y%5E2%2B9y%2B2\"
\n" ); document.write( "The factors, if this can be factored, will take the form:
\n" ); document.write( "\"%28ay%2Bm%29%28by%2Bn%29\" where:
\n" ); document.write( "a*b = 10 This is the coefficient of the first term.
\n" ); document.write( "m*n = 2 This is the constant term.
\n" ); document.write( "a*n+b*m = 9 This is the coefficient of the middle term.
\n" ); document.write( "Now you have to try a few combinations.
\n" ); document.write( "Try a = 5 and b = 2, so a*b = 10
\n" ); document.write( "Try m = 2 and n = 1, so m*n = 2
\n" ); document.write( "Then: an+bm = 5*1 + 2*2 = 5+4 = 9
\n" ); document.write( "Putting it all together, you'll get:
\n" ); document.write( "\"10y%5E2%2B9y%2B2+=+%285y%2B2%29%282y%2B1%29\"
\n" ); document.write( "Check, using FOIL:
\n" ); document.write( "\"%285y%2B2%29%282y%2B1%29+=+10y%5E2%2B5y%2B4y%2B2\" Simplify: \"10y%5E2%2B9y%2B2\"
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