document.write( "Question 71147: The perimeter of a rectangle is 32\", and the area is 60 square inches. Find the length and width of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #50869 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Let L=length and h=height. In this case the equations for perimeter and area are:
\n" ); document.write( "2L+2h=32 and L*h=60
\n" ); document.write( "L=60/h
\n" ); document.write( "Now plug in L=60/h for L in the previous equation
\n" ); document.write( "\"2%2860%2Fh%29%2B2h=32\"
\n" ); document.write( "\"120%2Fh%2B2h%5E2%2Fh=32\"Multiply 2nd term on left side to reach common denominator
\n" ); document.write( "\"%28120%2B2h%5E2%29%2Fh=32\"Multiply both sides by h
\n" ); document.write( "\"%28120%2B2h%5E2%29=32h\"Get everything to one side by subtraction
\n" ); document.write( "\"2h%5E2-32h%2B120=0\"Now we have a quadratic to solve. Use the quadratic equation to solve.\r
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ah%5E2%2Bbh%2Bc=0\" (in our case \"2h%5E2%2B-32h%2B120+=+0\") has the following solutons:
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\n" ); document.write( " \"h%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-32%29%5E2-4%2A2%2A120=64\".
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\n" ); document.write( " Discriminant d=64 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28--32%2B-sqrt%28+64+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"h%5B1%5D+=+%28-%28-32%29%2Bsqrt%28+64+%29%29%2F2%5C2+=+10\"
\n" ); document.write( " \"h%5B2%5D+=+%28-%28-32%29-sqrt%28+64+%29%29%2F2%5C2+=+6\"
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\n" ); document.write( " Quadratic expression \"2h%5E2%2B-32h%2B120\" can be factored:
\n" ); document.write( " \"2h%5E2%2B-32h%2B120+=+2%28h-10%29%2A%28h-6%29\"
\n" ); document.write( " Again, the answer is: 10, 6.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+2%2Ax%5E2%2B-32%2Ax%2B120+%29\"
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\n" ); document.write( "So the height is either 6 or 10. Lets solve for L.
\n" ); document.write( "\"10L=60\"
\n" ); document.write( "\"L=60%2F10\"
\n" ); document.write( "\"L=6\"If h=10 then L=6
\n" ); document.write( "\"6L=60\"
\n" ); document.write( "\"L=60%2F6\"
\n" ); document.write( "\"L=6\"If h=6 then L=10, see a pattern?
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